سؤال بخصوص ال subnetting ارجو المحترفين الدخول

[medo8000]

ممكن شرح مبسط لو عندي ip و عايز اعملة تقسيم ..ممكن ابسطة طريقة اعمل بيها التقسيم ...

لاني الصراحة سمعت الشرح بتاع المهندي ياسر رمزي والمهندس محمد سمير .. بس بردة الموضوع مبهم بالنسبالي

يعني مثلا انا عندي
192.168.10.0
ومعايا subnet mask 255.255.255.0
وعايز اقسم دة ل 8 شبكات

ممكن شرح عملي بسيط للحوار دة ...

[Creed]

موجود عنا 192.168.10.0 يعني class C.
بدك تقسمها ل 8 شبكات؟

الخطوه الاولى :





8 subnet - - > 2^n -2 >= 8


you need to know how much is "n"?


2^1-2>=8 wrong
2^2-2>=8 wrong
2^3-2>=8 wrong
2^4-2>=8 yes


So n = 4


we have class c = 255.255.255.0 = 1111111.11111111.11111111.11110000
so the class is 255.255.255.240

[demon_666]

alslamo alykom


u have the class c ip : 192.168.10.0 with mask 255.255.255.0 and u need to devide it into 8 subnets



2^3=8


so u will take the most signifcant 3 bits of the mask (i.e 255.255.255.XXXYYYYY) and then if u calclate the value for this subnet it will give u the subnet 255.255.255.224 as the summation of the x+x+x = 32+64+128


so u now have the subnet which will devide ur ip

the second part is to assign the number of hosts avilable y+y+y+y+y = 16+8+4+2+1=31
so u have avilable host address from 0:31 (i.e32 address) and ofcourse u know that the first address for network and the last one is for broadcast,so


net0
net address : 192.168.10.0
avilable addresses : 192.168.10.1:192.168.10.30
broadcast address : 192.168.10.31
CIDR notation : 192.168.10.0/255.255.255.224


net1
net address : 192.168.10.32
avilable addresses : 192.168.10.33 : 192.168.10.62
broadcast address : 192.168.10.63
CIDR notation : 192.168.10.32/255.255.255.224


and so on walaho a3lam


i hope that will be informative for u